0098132人目の素数さん垢版 | 大砲2018/05/08(火) 12:20:56.12ID:rSTdfkqz >>96 ∫f(x)dx = (1/a)∫sin(ax)/x dx = (1/a)Si(ax), ∫{f(x)}^2 dx = ∫{sin(ax)/ax}^2 dx = - {sin(ax)}^2 /(aax) + (1/a)∫sin(2ax)/x dx = - {sin(ax)}^2 /(aax) + (1/a)Si(2ax), にて簡単