0700132人目の素数さん垢版 | 大砲2018/09/11(火) 07:28:10.88ID:cF4T1n2w >>699 (a-1)x + (b-1)y +(c-1)z = 0 をみたすとき a log(a) = -a log(1/a) ≧ -a(1/a -1) = a-1, b log(b) ≧ b-1, c log(c) ≧ c-1, ax log(a) + by log(b) + cz log(c) ≧ (a-1)x + (b-1)y + (c-1)z = 0,