0484132人目の素数さん
2018/03/21(水) 04:59:29.95ID:Y0EoMfqc{√k + √(k+1)}/2 < ∫[k,k+1] √x dx =(2/3){(k+1)^(3/2)- k^(3/2)},
を用いて次を示せ。
(2) √2 < 99/70 = 1.41428571… (k=8)
√2 > 1393/985 = 1.41421320… (k=49)
√2 < (19601/6)/2310 = 1.4142135642… (k=288)
(3) √3 < (1351/6)/130 = 1.73205128… (k=48)
(5) √5 < 2889/1292 = 2.236068111… (k=80)
(6) √6 < (485/6)/33 = 2.4494949… (k=24)
(7) √7 < 2024/765 = 2.645751634… (k=63)
(10) √10 > 117/37 = 3.16216216… (k=9)
√10 < (27379/6)/1443 = 3.1622776622… (k=360)
(11) √11 < 3970/1197 = 3.316624895… (k=99)
(17) √17 > 268/65 = 4.123076923… (k=16)
(37) √37 > 882/145 = 6.08275862… (k=36)
面白スレ26 - 109〜110,117