>>545
r^(p-1) = p のとき
r = (p)^(1/(p-1))
x : z = x : x+p^(1/(p-1))

r^(p-1) = 100p のとき
r = (100p)^(1/(p-1))
x : z = x : x+ (100p)^(1/(p-1))

自明だろうか?