0192132人目の素数さん
2019/08/17(土) 10:52:37.17ID:+5QXhyrzおまえ(^^
but other people argue it's not ok, because we would need to define a measure on sequences,
Pruss(^^
if i is chosen uniformly independently of that strategy (where the "independently" here isn't in the probabilistic sense), we win with probability at least (n−1)/n. That's right.
Prussは間違いを認めた。未だに認められないのはおまえ一人(^^;