■初等関数研究所■
■ このスレッドは過去ログ倉庫に格納されています
初等関数(しょとうかんすう、英: Elementary function)とは、
実数または複素数の1変数関数で、代数関数、指数関数、対数関数、
三角関数、逆三角関数および、それらの合成関数を作ることを
有限回繰り返して得られる関数のことである
ガンマ関数、楕円関数、ベッセル関数、誤差関数などは初等関数でない
初等関数のうちで代数関数でないものを初等超越関数という
双曲線関数やその逆関数も初等関数である
初等関数の導関数はつねに初等関数になる 第一種の合流型超幾何関数(クンマー)
1F1[a; b; z] = 1+Σ[k=1, ∞] {a(a+1)・・・・(a+k-1)/b(b+1)・・・・(b+k-1)} z^k/k!
1F1[-n; -2n; z] = {n!/(2n)!} Σ[k=0, n] {(2n-k)!/(n-k)!k!} z^k 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
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sgssl;slg;ld;l 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
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J8hGG9KXTgycc8wu65xqHO4p5z5oqxLBQRZuY5NdFK6pM1UaaUzIAlBvvWS49LKCsiIbUDX0KKFIWjAdkRpo4aZkTjXtlBABqjBeDgeH64Kv8QRCkv4NklJWJU6uagXQG8uqws2ZLhzyEs04D6ycyNc9s3LAeDaywG9mQ3jlBFhHE7ba2qlDJlN9ixypMXRleRQZWryk
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SDK4t8ql63OVBPRjJe2DvhC0BHjXErI2RCeGdMeBPD539aNqdFVIPGHN1NIVVDyTM4gfJbnFDgC5slKjSO17coT9jUfpOvezlHg9lXM95eftZiKzTx36T6C88TnssEI0tM3SKlDidfP9neTR3feD1cDGkYAzaPDCjyD4a2OcqNChan0XweFrq0xqQYc6Oi6am5DWfurQ
Kvr3idZa3OUlonClNyGyT3u2Xrtde47Cr6m4tG1j7AurlCjmUXvLPaQDQLlhymjaNIkWblKiKeVhk601XohEk7mNq3FyXjLGTJjx4csGI9MHt9vijbaaAQMFGIi8A28SQA1Ie3oELhvKeuLzK9ZYmGMEVqj4GtOgB719u1e1KHHqpfnGgwmMFMpRTjoTrEl4f9KFathh
kjasjfkajkljfklajjfjksdjksjalkjflkjasjfkjasjfkjajjs2333354994998989029929050295895028902802058299202095898582982092029209029029
sgssl;slg;ld;l 例えば、6なら、
6→3→10→5→16→8→4→2→1
のように、偶数なら2で割り、奇数なら3倍に1を足すのを
繰り返して、1になるまでの回数(∈N)
この数列がすべての自然数で定義されるかどうかの
証明は知りません 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
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sgssl;slg;ld;l 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
43bDtYxhwTZApiRugaYbzsFfDKZmuR212sTlb3HrYDe9jytaLBgeojHWZxPkzLDqO3djDHR4YEE7wySKMFA1WfilujRqD7izkWmcUWhFiRZrxFJAByshrPMNynEJEpGtdOg7Qx1jjMcB2nGphazIOhgkUuKFgGIiMh65hqcNYbtLdSVeTIncn2bR8pUncW95wGWymgC0
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5f1wRmcZzXXh9xqvyHtHqtXG06b6iQ5OhfrAUZwU8Scwkh52X7iNRot4vwSfMrmjYoGlVIvhK9djdlkiGy03ly9O6SmKKfkBYZJCK8zLNCJux0nBGVJWVe90kIjRFBTCjOfe11bfeVXfLUM9mLp0zyFrfY4a1dC7nS9pShB2iDxRGp6Vn2SlReeXnc6mqJ6KfhY9L8gR
G1SMJQYyXNSnrSkV2JyMHPsH4umT9610YnFgDQnLn67betRIHPmdDewhiu5kGTYKxytAxhC1qJPuOVRw5q7ZpELCBwYEixZs6kmHkla4fdAZ5HQw7xnySrJ28cGOloZuerh0QEG6xb3JxuzHxFGdBWtgEy5decyx9iZpMlo5QVT14hFNLnp0zlcAGUfEdxAMjUP3lHkv
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kjasjfkajkljfklajjfjksdjksjalkjflkjasjfkjasjfkjajjs2333354994998989029929050295895028902802058299202095898582982092029209029029
sgssl;slg;ld;l Table[(1!/(1-k)!)/k!,{k,1,20}]
{1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0} 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
43bDtYxhwTZApiRugaYbzsFfDKZmuR212sTlb3HrYDe9jytaLBgeojHWZxPkzLDqO3djDHR4YEE7wySKMFA1WfilujRqD7izkWmcUWhFiRZrxFJAByshrPMNynEJEpGtdOg7Qx1jjMcB2nGphazIOhgkUuKFgGIiMh65hqcNYbtLdSVeTIncn2bR8pUncW95wGWymgC0
J8hGG9KXTgycc8wu65xqHO4p5z5oqxLBQRZuY5NdFK6pM1UaaUzIAlBvvWS49LKCsiIbUDX0KKFIWjAdkRpo4aZkTjXtlBABqjBeDgeH64Kv8QRCkv4NklJWJU6uagXQG8uqws2ZLhzyEs04D6ycyNc9s3LAeDaywG9mQ3jlBFhHE7ba2qlDJlN9ixypMXRleRQZWryk
5f1wRmcZzXXh9xqvyHtHqtXG06b6iQ5OhfrAUZwU8Scwkh52X7iNRot4vwSfMrmjYoGlVIvhK9djdlkiGy03ly9O6SmKKfkBYZJCK8zLNCJux0nBGVJWVe90kIjRFBTCjOfe11bfeVXfLUM9mLp0zyFrfY4a1dC7nS9pShB2iDxRGp6Vn2SlReeXnc6mqJ6KfhY9L8gR
G1SMJQYyXNSnrSkV2JyMHPsH4umT9610YnFgDQnLn67betRIHPmdDewhiu5kGTYKxytAxhC1qJPuOVRw5q7ZpELCBwYEixZs6kmHkla4fdAZ5HQw7xnySrJ28cGOloZuerh0QEG6xb3JxuzHxFGdBWtgEy5decyx9iZpMlo5QVT14hFNLnp0zlcAGUfEdxAMjUP3lHkv
UHzFXQXLWlU2JyYfOkcUjg40eeXu8e77qS4rgvjHWwxRbA1IKsNmn3CR9ePAuumjHnrWXeVuNStOENI4pHd7a7EwvoL8D7oenfbfeVoMT4Jho808YluyiYSEkfV5E6qPA5SiIWgl3G2zIc1NGsEW0nQuGTP504IXiRebMTKIEZyBdIqgQg1tOUYg7LzaYKiKixwj59ph
cILXg6ToA2TskeIlZraUTbzQ5PkR9lGnJjBFN7aSfv8vkCEpe9hYmrfF47H0RcNX5k3Y3i5xgHKhiNu5T8GeXfcYWpG6eLzIDAFy8DF39cqoofzCDnk8Ogt5q2H4cQNTgsDQDYYmFl2kKkYeX6CZ9LQruT8LprERVMyn0lUCYqfO4sQqWCu8kiVnpdZgd9QqdVcOT639
SDK4t8ql63OVBPRjJe2DvhC0BHjXErI2RCeGdMeBPD539aNqdFVIPGHN1NIVVDyTM4gfJbnFDgC5slKjSO17coT9jUfpOvezlHg9lXM95eftZiKzTx36T6C88TnssEI0tM3SKlDidfP9neTR3feD1cDGkYAzaPDCjyD4a2OcqNChan0XweFrq0xqQYc6Oi6am5DWfurQ
Kvr3idZa3OUlonClNyGyT3u2Xrtde47Cr6m4tG1j7AurlCjmUXvLPaQDQLlhymjaNIkWblKiKeVhk601XohEk7mNq3FyXjLGTJjx4csGI9MHt9vijbaaAQMFGIi8A28SQA1Ie3oELhvKeuLzK9ZYmGMEVqj4GtOgB719u1e1KHHqpfnGgwmMFMpRTjoTrEl4f9KFathh
kjasjfkajkljfklajjfjksdjksjalkjflkjasjfkjasjfkjajjs2333354994998989029929050295895028902802058299202095898582982092029209029029
sgssl;slg;ld;l 2n x 2n の正方形を
1 x 2 のドミノで埋める場合の数を考えます
たとえば、2x2の正方形を1x2のドミノで埋める場合の数は、2通りです
4x4の正方形を1x2のドミノで埋める場合の数は、36通りです
一般に、n=0,1,2,3,,,,のとき、
1, 2, 36, 6728, 12988816, 258584046368,,,
となり、一般項は、
Π[j=1 to n]Π[k=1 to n]{4cos^2 πj/(2n+1)+4cos^2 πk/(2n+1)}
となるようなのですが、
どのようにその公式が導かれるのでしょうか? 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
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5f1wRmcZzXXh9xqvyHtHqtXG06b6iQ5OhfrAUZwU8Scwkh52X7iNRot4vwSfMrmjYoGlVIvhK9djdlkiGy03ly9O6SmKKfkBYZJCK8zLNCJux0nBGVJWVe90kIjRFBTCjOfe11bfeVXfLUM9mLp0zyFrfY4a1dC7nS9pShB2iDxRGp6Vn2SlReeXnc6mqJ6KfhY9L8gR
G1SMJQYyXNSnrSkV2JyMHPsH4umT9610YnFgDQnLn67betRIHPmdDewhiu5kGTYKxytAxhC1qJPuOVRw5q7ZpELCBwYEixZs6kmHkla4fdAZ5HQw7xnySrJ28cGOloZuerh0QEG6xb3JxuzHxFGdBWtgEy5decyx9iZpMlo5QVT14hFNLnp0zlcAGUfEdxAMjUP3lHkv
UHzFXQXLWlU2JyYfOkcUjg40eeXu8e77qS4rgvjHWwxRbA1IKsNmn3CR9ePAuumjHnrWXeVuNStOENI4pHd7a7EwvoL8D7oenfbfeVoMT4Jho808YluyiYSEkfV5E6qPA5SiIWgl3G2zIc1NGsEW0nQuGTP504IXiRebMTKIEZyBdIqgQg1tOUYg7LzaYKiKixwj59ph
cILXg6ToA2TskeIlZraUTbzQ5PkR9lGnJjBFN7aSfv8vkCEpe9hYmrfF47H0RcNX5k3Y3i5xgHKhiNu5T8GeXfcYWpG6eLzIDAFy8DF39cqoofzCDnk8Ogt5q2H4cQNTgsDQDYYmFl2kKkYeX6CZ9LQruT8LprERVMyn0lUCYqfO4sQqWCu8kiVnpdZgd9QqdVcOT639
SDK4t8ql63OVBPRjJe2DvhC0BHjXErI2RCeGdMeBPD539aNqdFVIPGHN1NIVVDyTM4gfJbnFDgC5slKjSO17coT9jUfpOvezlHg9lXM95eftZiKzTx36T6C88TnssEI0tM3SKlDidfP9neTR3feD1cDGkYAzaPDCjyD4a2OcqNChan0XweFrq0xqQYc6Oi6am5DWfurQ
Kvr3idZa3OUlonClNyGyT3u2Xrtde47Cr6m4tG1j7AurlCjmUXvLPaQDQLlhymjaNIkWblKiKeVhk601XohEk7mNq3FyXjLGTJjx4csGI9MHt9vijbaaAQMFGIi8A28SQA1Ie3oELhvKeuLzK9ZYmGMEVqj4GtOgB719u1e1KHHqpfnGgwmMFMpRTjoTrEl4f9KFathh
kjasjfkajkljfklajjfjksdjksjalkjflkjasjfkjasjfkjajjs2333354994998989029929050295895028902802058299202095898582982092029209029029
sgssl;slg;ld;l FromDigits[{1,0,1,0,0,1,0,0}, 2]
164 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
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Kvr3idZa3OUlonClNyGyT3u2Xrtde47Cr6m4tG1j7AurlCjmUXvLPaQDQLlhymjaNIkWblKiKeVhk601XohEk7mNq3FyXjLGTJjx4csGI9MHt9vijbaaAQMFGIi8A28SQA1Ie3oELhvKeuLzK9ZYmGMEVqj4GtOgB719u1e1KHHqpfnGgwmMFMpRTjoTrEl4f9KFathh
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sgssl;slg;ld;l 0qc3OXjXwBt1HD7Mt228BdYw7VinFEl43Zoc9tkhSu6hmEi1WEZ6OqB3FSe3k7L0qXrj8fNHrzBhhPTzD8WhAjrDXv1k55mQkf5uiOqjKuWUGgYFZuNZUagqAX9wNZzwaH4BlgoDtLscwycAwYQ7tuMa9CoGneWU5TXTTYEhxrUUJB0qmsR19UqgNcuwuN3oX8QyXNG
43bDtYxhwTZApiRugaYbzsFfDKZmuR212sTlb3HrYDe9jytaLBgeojHWZxPkzLDqO3djDHR4YEE7wySKMFA1WfilujRqD7izkWmcUWhFiRZrxFJAByshrPMNynEJEpGtdOg7Qx1jjMcB2nGphazIOhgkUuKFgGIiMh65hqcNYbtLdSVeTIncn2bR8pUncW95wGWymgC0
J8hGG9KXTgycc8wu65xqHO4p5z5oqxLBQRZuY5NdFK6pM1UaaUzIAlBvvWS49LKCsiIbUDX0KKFIWjAdkRpo4aZkTjXtlBABqjBeDgeH64Kv8QRCkv4NklJWJU6uagXQG8uqws2ZLhzyEs04D6ycyNc9s3LAeDaywG9mQ3jlBFhHE7ba2qlDJlN9ixypMXRleRQZWryk
5f1wRmcZzXXh9xqvyHtHqtXG06b6iQ5OhfrAUZwU8Scwkh52X7iNRot4vwSfMrmjYoGlVIvhK9djdlkiGy03ly9O6SmKKfkBYZJCK8zLNCJux0nBGVJWVe90kIjRFBTCjOfe11bfeVXfLUM9mLp0zyFrfY4a1dC7nS9pShB2iDxRGp6Vn2SlReeXnc6mqJ6KfhY9L8gR
G1SMJQYyXNSnrSkV2JyMHPsH4umT9610YnFgDQnLn67betRIHPmdDewhiu5kGTYKxytAxhC1qJPuOVRw5q7ZpELCBwYEixZs6kmHkla4fdAZ5HQw7xnySrJ28cGOloZuerh0QEG6xb3JxuzHxFGdBWtgEy5decyx9iZpMlo5QVT14hFNLnp0zlcAGUfEdxAMjUP3lHkv
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kjasjfkajkljfklajjfjksdjksjalkjflkjasjfkjasjfkjajjs2333354994998989029929050295895028902802058299202095898582982092029209029029
sgssl;slg;ld;l Table[sum[C(2n-1+α,k-1),{n,1,a}],{k,1,b}]
a=n(n+1)/2-1
b=n(n+1)
を満たす差分追尾数列αを見つけてくれ〜(・ω・)ノ 2 3 6 7 9
2 3 6 7 8 12 13 15 17
2 3 6 7 8 12 13 14 16 20 21 23 25 27
2 3 6 7 8 12 13 14 15 20 21 22 24 26 30 31 33 35 37 39
2 3 6 7 8 12 13 14 15 20 21 22 23 25 30 31 32 34 36 38 42 43 45 47 49 51 53
長軸choose数え上げ ■高校生がDDoS攻撃で国内初検挙! 青少年のサイバー犯罪の驚異
2014年10月01日 18時15分更新 ■連続投稿・重複
連続投稿・コピー&ペースト
連続投稿で利用者の会話を害しているものは削除対象になります
個々の内容に違いがあっても、荒らしを目的としていると判断したものは同様です
コピー&ペーストやテンプレートの存在するものは、アレンジが施してあれば
残しますが、全く変更されていない・一部のみの変更で内容の変わらないもの、
スレッドの趣旨と違うもの、不快感を与えるのが目的なもの、
などは荒らしの意図があると判断して削除対象になります
※お手数ですが削除依頼できる方お願いします<(_ _)> ■書き込む前におやくそく
近頃、初心者さんが増えてきたので、お約束をつくってみました
基本的には、ユーザーの良識に任せたいのですが、
「明文化したルールがない」ということを逆手にとってなにをしてもいいと
誤解する人が多いので、、、
by ひろゆき
【ロビーのお約束】 削除の要件(禁止されること)
荒らし依頼・ブラクラの張付け等第3者に迷惑がかかる行為
アダルト広告・勧誘・悪質な掲示板宣伝などのアドレス等張りつけ
煽り・煽りに対する返答・叩き・誹謗中傷等(差別発言等含む)
コピペ・アスキーアート等必要以上の張り付け または
第3者に迷惑が掛かる行為や発言であった場合は削除対象にします トランプの束がある
2〜10までの数字が描かれたカードが各スートに1枚ずつと、
ジョーカーのカードが24枚ある
全てを混ぜて無作為に切り直して12枚のカードを無作為に引いたとき
その12枚のカードのうちジョーカー以外にいずれも違う数字が
書かれている確率はいくらか
Sum[choose(24,k)*choose(9,12-k)*4^(12-k),{k,3,12}]/(choose(60,12))
Sum[C(24,k)C(9,12-k)4^(12-k),{k,3,12}]/(C(60,12))
出力 7371811052/66636135475 >>532
Table[C(0,4mod n),{n,1,10}]
{1, 1, 0, 1, 0, 0, 0, 0, 0, 0} 短軸有利☆
Table[C(9,k-1)+C(7,k-1)+C(5,k-1)+C(4,k-1)+C(1,k-1),{k,1,12}]
Table[sum[C(2n-1+C(0,n-2),k-1),{n,1,5}],{k,1,12}]
{5, 26, 73, 133, 167, 148, 91, 37, 9, 1, 0, 0}
k-1を一つにして式を短縮 Table[C(0,n-1 mod7),{n,1,14}]
{1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0} ((-1)^n)(((-1)^n)n+n+4(-1)^n+2)/2
1 5 1 7 1 9 1 11 1 13 1 15 1 17 1 短軸有利☆
Table[C(9,k-1)+C(7,k-1)+C(5,k-1)+C(4,k-1)+C(1,k-1),{k,1,12}]
Cの数は宝一つの時の当たり数の5
9+7+5+4+1=26は宝二個の時の当たり数になる
長軸有利☆
Table[C(9,k-1)+C(7,k-1)+C(6,k-1)+C(3,k-1)+C(2,k-1),{k,1,12}]
Cの数は宝一つの時の当たり数の5
9+7+6+3+2=27は宝二個の時の当たり数になる 同様に20マスの場合は
短軸有利のCの数は宝一つの時の当たり数の9
17+15+13+11+10+8+5+4+1=84
長軸有利のCの数は宝一つの時の当たり数の9
17+15+13+12+8+7+6+3+2=83 ヤン・ルカン、ジェフリーヒントン、Yoshua Bengioの
3人がチューリング賞受賞した 100!中の二進数字の桁数を求める:
In[1]:=IntegerLength[100!, 2]
Out[1]=525 q1..q2..q3..q4
q5..q6..q7..q8
q9q10q11q12
p1..p4..p7..p10
p2..p5..p8..p11
p3..p6..p9..p12
同じ座標なら数字の小さいほうが勝ち
[q2とq10] & [p4とp6]に宝が配置された時は
互いに数字の小さいほうを選んで勝負
q2 vs p4 で q2の勝ちとなる
この後にq10とp6の探査をしても
情報としての価値はゼロ 1 個のサイコロを 10 回投げたとき,1 または 2 の目が
ちょうど 4 回出る確率を求めよ
P(4)=C(10,4)P^4Q^(10-4)
=C(10,4)(1/3)^4(2/3)^6 a_n = (-1/4 + i/4) ((-i)^n + i^(n + 1) + (-1 - i))
1 1 0 0 1 1 0 0 確率空間においては, A ∈ F を事象 (event) と呼ぶ. a_n = 1/4 ((-1)^n - (1 + 2 i) (-i)^n - (1 - 2 i) i^n + 9)
1, 3, 3, 2, 1, 3, 3, 2, 1, 3, 3, 2, 1, 3, 3, 2, 1, 3, 3, 2, 合流型超幾何微分方程式
(confluent hypergeometric differential equation) (a-b-c)(a+b-c)(a-b+c)(a+b+c)
a^4-2a^2b^2-2a^2c^2+b^4-2b^2c^2+c^4 ComplexExpand[(1+E^(I(1+n)Pi)+2n)/4] (n(n+1)/2-1)^2+(4n^3-6n^2-4n-3(-1)^n+3)/48 (n(n+1)/2-1)^2+(-4n^3+18n^2+28n-3(-1)^n-45)/48 0,1 の 2 値を扱う論理代数は,論理回路の設計や解析を行う
上での数学的基礎を与えるものである. 20世紀中頃になり,Shannon により論理代数に
基づく論理回路設計法が示された. >>843
ComplexExpand[(1+E^(I Pi+I n Pi)+2 n)/4] 関係スレに書き込む>>1を書込み禁止に、知ってる人がいたらお願いします >>1は荒らしなのでアクセス禁止に、知ってる方がいたらお願いします >>1はキチガイなのでアクセス禁止に、わかるかたお願いします ■ このスレッドは過去ログ倉庫に格納されています