>>994

>>961 より
1または4の目　j回
2または5の目　k回
3または6の目　(3n-j-k)回
出たとき
　S ≡ j-k　(mod 3)
　T ≡ j+k　(mod 3)

P(3|T) = P(j+k≡0)
　= Σ[L=0,3n] Ｃ[3n,L] (2/3)^L (1/3)^(3n-L) {1 +ω^L +ω^(-L)}/3
　= {(1/3 + 2/3)^(3n) + (1/3 + 2ω/3)^(3n) + (1/3 + 2/(3ω))^(3n)}/3
　= {1 + (i/√3)^(3n) + (-i/√3)^(3n)}/3
　= {1 + 2(1/3)^(3n/2)cos(nπ/2)}/3,

P(3|T ∧ 3|S) = P(j≡0 ∧ k≡0)
　= Σ[0≦j+k≦3n] (3n)!/{j! k! (3n-j-k)!} (1/3)^(3n) {1+ω^j +ω^(-j)}/3・{1+ω^k +ω^(-k)}/3
　= {(1/3+1/3+1/3)^(3n) + 2(1/3+1/3+ω/3)^(3n) + 2(1/3+1/3+1/3ω)^(3n) + (1/3+ω/3+ω/3)^(3n) + (1/3+1/3ω+1/3ω)^(3n) + 2(1/3+ω/3+1/3ω)^(3n)}/9
　= {1 + 2((2+ω)/3)^(3n) + 2((2+1/ω)/3)^(3n) + ((1+2ω)/3)^(3n) + ((1+2/ω)/3)^(3n) + 0^(3n)}/9
　= …