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**ご冗談でしょう？名無しさん** · 2010/12/07(火) 12:31:35

語れ

2016/07/10(日) 19:56:58.62

>>85
　ｅ = Γ(a) ｅ0,

　ａ = ｅｅ/(2chε0) = Γ(a)^2 ｅ0ｅ0/(2chε0) = ａ0,

　1/ａ0 = exp(ππ/2) = 139.0456366606487415630

We presume that the spin-related component in the coupling constant e, associated with vacuum polarization, is:
An electromagnetic coupling with a magnetic moment.

So, including a first anomaly term, we make the following guess, similar to Gordon decomposition:

　Γ(a) = 1 + [a (1 +a/2π)],

One could in principle derive an, exact to all order, value for the observable ａ value with unlimited precision:

　1/ａ = 137.035999528369196　　　（←やや大きい）

"A non-perturbative derivation of the exact value of the SU(2) coupling value g from the standard Electroweak Lagrangian itself"

http://chip-architect.com/physics/Electroweak_coupling_g.pdf 182KB
http://sci.physics.foundations.narkive.com/6yTJCRwE/a-non-perturbative-derivation-of-the-exact-value-of-the-su-2-coupling-value-g-from-the-standard

**ご冗談でしょう？名無しさん** · 2016/07/10(日) 20:03:16.32

>>867
（訂正）
　ａ = ｅｅ/(2ch.ε0) = Γ(a)^2 ｅ0ｅ0/(2ch.ε0) = Γ(a)^2 ａ0,