0867名無しさん@そうだ選挙に行こう! Go to vote!
2016/07/10(日) 19:56:58.62ID:???e = Γ(a) e0,
a = ee/(2chε0) = Γ(a)^2 e0e0/(2chε0) = a0,
1/a0 = exp(ππ/2) = 139.0456366606487415630
We presume that the spin-related component in the coupling constant e, associated with vacuum polarization, is:
An electromagnetic coupling with a magnetic moment.
So, including a first anomaly term, we make the following guess, similar to Gordon decomposition:
Γ(a) = 1 + [a (1 +a/2π)],
One could in principle derive an, exact to all order, value for the observable a value with unlimited precision:
1/a = 137.035999528369196 (←やや大きい)
"A non-perturbative derivation of the exact value of the SU(2) coupling value g from the standard Electroweak Lagrangian itself"
http://chip-architect.com/physics/Electroweak_coupling_g.pdf 182KB
http://sci.physics.foundations.narkive.com/6yTJCRwE/a-non-perturbative-derivation-of-the-exact-value-of-the-su-2-coupling-value-g-from-the-standard