a/b=2+1/b
a/b=(2b+1)/b
holds.
When m=2b+1, b=n,
a/b=m/n
holds. Since odd harmonic divisor numbers do not exist other than 1,
quasiperfect numbers which do not include 2 as a factor do not exit.
(2^(k+1)-1)a=2×2^k×b+1
a=(2^(k+1)×b+1)/(2^(k+1)-1)
a/b=(2^(k+1)×b+1)/(b(2^(k+1)-1))
When m=2^(k+1)×b+1, n=b(2^(k+1)-1), quasiperfect numbers do not exit in the same way.
From the above, it is proved that quasiperfect numberes do not exit. (Q.E.D.)
