0136132人目の素数さん垢版 | 大砲2023/04/12(水) 02:05:22.35ID:qqmT0g6P 1/(1-1/2^s-(1-1/2^s)*1/3^s-(1-1/2^s)*(1-1/3^s)*1/5^s-(1-1/2^s)*(1-1/3^s)*(1-1/5^s)*1/7^s-・・・-Π[k=1→n-1](1-1/p(k)^s)*1/p(n)^s) Σ(1/(a^n1*b^n2*c^n3)^s=1/(1-1/a^s-(1-1/a^s)*1/b^s-(1-1/a^s)*(1-1/b^s)*1/c^s)