高校数学の質問スレPart404

[0162 １３２人目の素数さん 2020/04/29(水) 14:17:32.16 ID:Mk0K+WWV]

1/(k-3)-1/(k-1)+1/(k+1)-1/(k+3)
= 1/(k-3)+1/(k-2)+1/(k+1)+1/(k+2)
-(1/(k-2)+1/(k-1)+1/(k+2)+1/(k+3))