>>525
Table[sum[C(2n-1+C(0,n-1)+C(0,n-3)+3C(1,n-5)+3C(1,n-9)+C(1,n-12)-19C(0,n-14)+C(0,n-15),k-1),{n,1,20}],{k,1,21}]
Table[sum[C(2n-1+C(0,3mod n)+3C(1,n-5)+3C(1,n-9)+C(1,n-12)-19C(0,n-14)+C(0,n-15),k-1),{n,1,20}],{k,1,21}]

さらに短く