【あさひ】高校数学の質問スレPart397 [無断転載禁止]©2ch.net

[0035 １３２人目の素数さん 2018/02/04(日) 21:38:08.23 ID:e/Db4a5+]

(d/dx)((3/8)x-(1/4)sin(2x)+(1/32)sin(4x))=3/8-(1/2)cos(2x)+(1/8)cos(4x)
=3/8-(1/2)(1-2(sin(x))^2)+(1/8)(1-8(sin(x))^2+8(sin(x))^4)
=(sin(x))^4