0388132人目の素数さん
2018/09/28(金) 09:40:21.64ID:phrHQfEJ漸化式から、n>>1 では
a[n] 〜 α{1 -1/(4n) -3/(32n^2) -1/(384n^3) +361/(6144n^4) +12799/(122880n^5) +(377221/2449120n^6) + …}
〜 α(1 - 1/n)^(1/4),
ここに α = lim(n→∞) a[n],
[前スレ.609] では
a[1] = 0, a[2] = 1/3, a[3] = 1/3, a[4] = 12/35, a[5] = 47/135,
a[6] = 731/2079, a[7] = 1772/5005, a[8] = 20609/57915,
a[9] = 1119109/3132675, a[10] = 511144/1426425, …, a[∞] = 1/e